User Defined Java Expression
Usage
If you have a Java expression like :
C=A+B
Then you can simply enter the right side of the expression in the dialog:
A+B
The values are exposed to the expressions as the Java objects they are :
Data type | Java Class |
---|---|
BigNumber | BigDecimal |
Binary | byte[] |
Date | java.util.Date |
Integer | java.lang.Long |
Number | java.lang.Double |
String | java.lang.String |
Options
Option | Description |
---|---|
Transform name | Specify a name for this transform. This must be unique wihin the pipeline. |
New field | The new field in the data stream that contains the result of the expression. If you want to overwrite an existing field, you need to define the same field here and in the "Replace value" option. |
Java expression | The Java expression to evaluate. See examples below. |
Value type | The field’s data type. |
Length | The maximum length of a string in the new field. |
Precision | The number of decimal places used to express numbers. |
Replace value | Set this to be identical to the "New field" name when you want to replace the value in an existing field. |
Examples
Add 2 integers, A and B
A+B
Concatenate 2 Strings : firstname and name and put a space in between
firstname+" "+name
or if you really care about performance, this might be faster:
new StringBuffer(firstname).append(" ").append(name).toString()
Use native Java and API functions
System.getProperty("os.name")
Business rules (If / Then / Else)
a<c?true:false
This can be more complicated
a<c?(a==1?1:2):3
even with OR and AND and other operators and functions
Using Constants
If you use a constant, you may need to define the right type in some expressions otherwise it could throw an error. Eg if you use "0" that is "int" but Apache Hop "Integer" is "java.lang.Long", so you’ll get an exception:
Incompatible expression types "int" and "java.lang.Long"
To solve this, use:
test == null ? new Long(0) : test
The above expression checks if "test" is null and replaces it with a zero Long. Otherwise, it return "test" unchanged.
Cut a string from end and test for null and minimal length
Imagine you have input strings "location" like
Orlando FL New York NY
and you want to separate the state and city. You could use the following expressions:
For state (get the last 2 characters):
location != null && location.length()>2 ? location.substring(location.length()-2, location.length()) : null
For city (get the beginning without the last 2 characters and trim):
location != null && location.length()>2 ? location.substring(0, location.length()-2).trim() : location
Functionality of a LIKE operator (contains string)
The following example returns 1 when abc is within the source string, otherwise 2. It returns also 2 when the source string is null. If you prefer the return values to be of value type Integer, use "new Long(1)" and "new Long(2)".
samplestr != null && samplestr.indexOf("abc")>-1 ? 1 : 2
Blocking specific code
As a simple security measure you can block the execution of code containing specific strings. This can be done by adding exclusions to the codeExclusions.xml
file located at <Hop Installation>/plugins/transforms/janino
Example:
<exclusions>
<exclusion>System.</exclusion>
<exclusion>HopVfs.</exclusion>
</exclusions>